Which of the following will occur when a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq)?

A.) A precipitate of KNO3 will form; Pb2+ and I– are spectator ions.
B.) A precipitate of Pb(NO3)2 will form; K+ and I– are spectator ions.
C.) A precipitate of PbI2 will form; Pb2+ and I– are spectator ions.
D.) A precipitate of PbI2 will form; K+ and NO3– are spectator ions.
E.) No precipitate will form.

What will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq) is;

Option D; A precipitate of PbI2 will form; K+ and NO3– are spectator ions.

We want to find what will happen when Pb(NO3)2(aq) is mixed with a solution of KI(aq)

Let us write a balanced equation of this reaction.

Pb(NO3) 2 (aq) + 2KI(aq) = PbI2(s) + 2KNO3(aq)

To answer this question properly, we need to write an ionic equation of the balanced equation above.

Let us first list all the ions present which are;

Pb2+(aq) + 2NO3-(aq) and K+(aq) + I-(aq)

Writing the ionic equation now gives us;

Pb2+(aq) + 2NO3-(aq) + K+(aq) + I-(aq) = PbI2(s) + 2K+(aq) + 2NO3-(aq)

In this ionic equation, we see that it formed PbI2(s) which is a precipitate.

Now, the ions 2K+(aq) + 2NO3-(aq) are on the same side and as such are not participating in the reaction. Thus, they can be called spectator ions.

Read more at; link

When a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq), a precipitate of PbI₂ will form; K⁺ and NO₃⁻ are spectator ions.

Explanation:

When an aqueous solution of lead nitrate (Pb(NO₃)₂ is mixed with aqueous solution of potassium iodide (KI), then there is a precipitate formation of lead iodide (PbI₂), and the potassium  (K⁺) ion and nitrate (NO₃⁻) ion acts as spectator ions that is ions do not involved in the reaction.

The reaction can be represented as,

Pb(NO₃)₂(aq) + 2 KI (aq) → PbI₂(s) + 2KNO₃(aq)

The ionic equation can be written as,

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + 2 I⁻(aq) →  PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

On both sides of the equation, we have K⁺ and NO₃⁻ ions, which gets cancelled, and these 2 ions are called as spectator ions.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year