Correct answer only !

enter the equations of the asymptotes for the function f(x) .

f(x) = −2/x + 4 − 6

 V.A.: x = -4,    H.A: y = -6

Step-by-step explanation:

Vertical Asymptote is the restriction on "x".  Since the denominator cannot be equal to zero, then x + 4 ≠ 0  ⇒  x ≠  -4. So, the vertical asymptote is at x = 4.

Horizontal Asymptote is the restriction on "y".  This is determined by the degree of the numerator compared to the degree of the denominator.  In the given problem, the degree of the numerator is less than the degree of the denominator so the horizontal asymptote is y = 0.  However, there is also a negative 6 after the rational expression so the horizontal asymptote is: y = 0 - 6  ⇒   y = -6

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2