In parallelogram abcd , diagonals ac and bd intersect at point e, be=2x^2−x , and de=x^2+6 . what is bd ?

BE = DE

2x^2-x = x^2+6

x^2-x-6 =0

(x+2) (x-3)

x = -2 or x = 3

1 solution using x = -2:

BE = 2(-2)^2 -(-2) = 10

DE = (-2)^2+6 = 10

10 +10 =20

2nd solution using x = 3

BE =2(3)^2-3 = 15

DE = (3)^2+6 =15

15+15 = 30

 The answer could be 20 or 30. Will need to try them both

 Would probably try 30 first ( maybe x can't be a negative number?)

b i think

step-by-step explanation:

not really sure